Saturday, November 21, 2009

math (1120) - Quad: y=a(x-u)^2

y=a(x+u)^2 or y=a(u-x)^2

with equations that look like this, we discovered thaat:

- a determines the concavity (if its negative it will point down)
- a also determines the steepness (wideness)
- u determines teh vertex (-u, 0)
solve bx + u = 0 for vertex (-u/b, 0)

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